[最も選択された] ƒƒ“ƒY ƒ{ƒu ƒ}ƒbƒVƒ… ˆá‚¢ 126512
O Ρ ȧQ0 Z x # x ?= q(u)q(v)2f(u,v) So f(u,v) = 1 2 (q(uv)−q(u)−q(v)) Let's look at an example Consider A = 2 1 1 0 it is a symmetric matrix Let f be the corresponding bilinear form We have f((x1,y1),(x2,y2)) = 2x1x2 x1y2 x2y1 and q(x,y) = 2x2 2xy = f((x,y),(x,y)) Let u = (x1,y1),v = (x2,y2) and let us calculate 1 2 (q(uv)−q(u)−q(v)) = 1 2 Mostrar que, se u ´e ortogonal a v e w, u ´e tamb´em ´e ortogonal a v w Soluc¸˜ao u = (x, y, z) v = (a, b, c) z = (e, f, g) Agora se u e ortogonal a v e w o produto escalar entre eles ´e 0 assim (x, y, z)(a, b, c) = 0, ou seja, uv = 0 (xa, yb, zc) = 0 (x, y, z)(e, f, g) = 0, ou seja, uz = 0 (xe, y f, zg) = 0 Agora vamos somar os V K Let U 7 2 Y 7 1 And A I J Chegg Com ƒƒ"ƒY ƒ{ƒu ƒ}ƒbƒVƒ… ˆá‚¢